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Proof by Mathematical Induction

Prove a statement is true for every whole number with two steps, the base case and the inductive step. Sums and divisibility.

Proof 4 min read 13 questions Jump to quiz

On this page

Starting point: what you already know

  • Sigma notation: .
  • From arithmetic series: .
  • Divisible by 3 means equal to for some whole number .
  • Algebra skills: factorising, expanding, finding a common denominator.

Why we need proof

The pattern , , suggests that the first odd numbers add to . Checking more examples makes it believable, but checking a million cases still does not prove it for the next one. Induction proves it for every at once.

The structure

Let be the statement you want to prove.

The assumption in step 2 is called the inductive hypothesis. You are not assuming what you want to prove. You are proving "if it works for one domino, it works for the next".

Proving sums

Proving divisibility

Mathematical induction
Idea
  • First domino falls
  • Each one knocks the next
Steps
  • Base case n = 1
  • Assume true for n = k
  • Prove for n = k + 1
  • Write the conclusion
Sums
  • Add the next term to both sides
Divisibility
  • Write as divisor × M
  • Substitute and factor
Errors
  • No base case
  • Inductive step fails

Quick summary

  • Induction has two steps: prove the base case, then show that if it is true for , it is true for .
  • For sums, add the next term to the assumed sum and simplify to the target.
  • For divisibility, write the assumption as divisor , substitute, then factor out the divisor.
  • Finish with the conclusion sentence. Missing either step means there is no proof.

Quiz

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Mathematics Extension 1 chapters

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