In short: Organic compounds are identified with chemical tests and instruments. Mass spectrometry gives the molar mass, infrared spectroscopy shows functional groups like O−H and C=O, and NMR spectroscopy shows the different carbon and hydrogen environments, which together reveal the structure.
Chemical tests for functional groups
| Group | Test | Positive result |
|---|---|---|
| C=C (alkene) | Bromine water | Orange-brown to colourless, quickly |
| −OH (1° or 2° alcohol) | Acidified , warm | Orange to green |
| −OH (3° alcohol) | Acidified , warm | No change |
| −COOH (carboxylic acid) | or | Fizzes () |
| −COOH | Blue litmus | Turns red |
| −NH₂ (amine) | Red litmus | Turns blue |
| Aldehyde vs ketone | Acidified dichromate | Aldehyde: orange to green. Ketone: no change |
Chemical tests are cheap and quick, but they use up the sample and only tell you about one group at a time.
Mass spectrometry (MS)
A mass spectrometer measures the mass of a molecule and its fragments.
- Ionisation: a beam of high-energy electrons knocks an electron off each molecule, making a positive ion, .
- Acceleration: the ions are sped up by an electric field.
- Deflection: a magnetic field bends their paths. Lighter ions bend more.
- Detection: ions are counted at each mass-to-charge ratio, .
The sample is destroyed in the process.
Reading a mass spectrum:
- The molecular ion peak () is the peak with the highest (ignore tiny peaks at M+1 from carbon-13). It gives the molar mass.
- The base peak is the tallest peak, set to 100%. It is the most stable fragment.
- Other peaks are fragments. The difference from M tells you what broke off.
| (or mass lost) | Fragment |
|---|---|
| 15 | (loss of 15 = lost ) |
| 29 | or |
| 31 | |
| 43 | or |
| 45 | |
| Loss of 17 | lost OH |
| Loss of 18 | lost |
Chlorine and bromine show two molecular ion peaks, 2 apart, because of their isotopes: Cl gives M and M+2 in a 3 : 1 ratio; Br gives M and M+2 in a 1 : 1 ratio.
Infrared (IR) spectroscopy
Bonds vibrate (stretch and bend). Each type of bond absorbs infrared radiation at its own wavenumbers (in cm⁻¹). An IR spectrum shows troughs (low transmittance) where the sample absorbs.
| Bond | Wavenumber (cm⁻¹) | Look |
|---|---|---|
| O−H (alcohol) | 3230 to 3550 | Broad |
| O−H (carboxylic acid) | 2500 to 3000 | Very broad |
| N−H (amine, amide) | 3300 to 3500 | Medium, sharper |
| C−H | 2850 to 3300 | Sharp |
| C=O (aldehyde, ketone, acid, ester, amide) | 1680 to 1750 | Strong and sharp |
| C=C | 1620 to 1680 | |
| C−O | 1000 to 1300 |
The region below 1500 cm⁻¹ is the fingerprint region: complex, but unique to each molecule. It can confirm an identity by matching a known spectrum.
IR tells you which functional groups are present, but not how many or where.
Carbon-13 NMR
Some nuclei, including and , behave like tiny magnets. In a strong magnetic field they absorb radio waves. The exact frequency depends on the atom's chemical environment (what it is bonded to). This is nuclear magnetic resonance.
In a NMR spectrum:
- The number of peaks = the number of different carbon environments.
- The chemical shift (in ppm) shows what each carbon is near.
- Peak heights are not used for counting.
| Carbon type | Shift (ppm) |
|---|---|
| C−C (alkane) | 5 to 40 |
| C−Cl or C−Br | 10 to 70 |
| C−O (alcohol, ether, ester) | 50 to 90 |
| C=C | 90 to 150 |
| C=O (acid, ester, amide) | 160 to 185 |
| C=O (aldehyde, ketone) | 190 to 220 |
Carbons in symmetrical positions are equivalent. Propanone, , has only 2 environments (both are the same).
Proton (¹H) NMR
A ¹H NMR spectrum gives three pieces of information:
- Number of peak sets = number of different hydrogen environments.
- Area under each set (or the given ratio) = the number of H in that environment.
- Splitting: a set of peaks is split by the H on neighbouring carbons. The n + 1 rule: neighbouring H atoms split a signal into peaks.
| Neighbouring H | Peaks | Name |
|---|---|---|
| 0 | 1 | Singlet |
| 1 | 2 | Doublet |
| 2 | 3 | Triplet |
| 3 | 4 | Quartet |
| 6 | 7 | Septet |
H on O−H or N−H is usually a singlet and does not split its neighbours.
| Hydrogen type | Shift (ppm) |
|---|---|
| R−CH₃, R−CH₂−R | 0.9 to 1.7 |
| −C=O | 2.0 to 2.7 |
| −CH−O (next to O) | 3.3 to 4.5 |
| R−OH | 1 to 6 (variable) |
| −CHO (aldehyde) | 9 to 10 |
| −COOH | 9 to 13 |
Putting it together
| Technique | Tells you |
|---|---|
| Chemical tests | Presence of a functional group |
| Mass spectrometry | Molar mass and fragments |
| Infrared | Functional groups (bond types) |
| ¹³C NMR | Number and type of carbon environments |
| ¹H NMR | Number, type and neighbours of hydrogen environments |
No single technique is enough to be sure. Use them together:
- Find the molar mass from MS (and the formula, if percentage composition is given).
- Find the functional groups from IR and chemical tests.
- Count environments with ¹³C and ¹H NMR.
- Use splitting to join the pieces.
- Check your final structure against every piece of data.
- Bromine water: C=C
- Dichromate: 1°, 2° alcohol, aldehyde
- Carbonate: acid
- Molecular ion: molar mass
- Base peak: tallest
- Fragments
- Cl 3:1, Br 1:1
- O−H broad
- C=O 1680 to 1750
- Fingerprint region
- Peaks = C environments
- Shift shows type
- Sets = H environments
- Area = number of H
- n + 1 splitting
- Check all data
Quick summary
- Chemical tests: bromine water (C=C), dichromate (1° and 2° alcohols, aldehydes), carbonate (acids).
- MS: molecular ion gives molar mass; fragments show pieces. Sample is destroyed.
- IR: broad O−H at 3230 to 3550 (alcohol) or 2500 to 3000 (acid); C=O at 1680 to 1750 cm⁻¹.
- ¹³C NMR: number of peaks = number of carbon environments.
- ¹H NMR: number of sets, peak areas and n + 1 splitting.
- Combine all the data and check the structure fits every piece.
Quiz
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Which test shows a C=C double bond?
- A Bromine water turns colourless
- B Sodium carbonate fizzes
- C Litmus turns blue
- D Dichromate stays orange
Show answer
A: Bromine water turns colourless
Bromine adds across the double bond.
In mass spectrometry, the molecular ion peak gives:
- A The number of carbon environments
- B The molar mass
- C The functional groups
- D The boiling point
Show answer
B: The molar mass
has the mass of the whole molecule.
The base peak in a mass spectrum is:
- A The peak with the highest
- B The tallest peak
- C The first peak
- D Always at 15
Show answer
B: The tallest peak
It is the most abundant ion, set to 100%.