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Simple Interest, Compound Interest and Depreciation
How money grows and how assets lose value. Simple and compound interest, compounding periods and depreciation.
Financial Mathematics · 5 min read · Updated ·13 questions ·Jump to quiz·Feedback
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In short: Simple interest grows by the same amount each period, I=Prn, while compound interest grows by the same percentage, A=P(1+r)n. Depreciation is the same idea in reverse: an item loses value by a fixed percentage each year, S=V0(1−r)n.
Starting point: Years 9 and 10
Simple interest
Simple interest is paid only on the original amount, the principalP.
I=Prn
r is the rate per period as a decimal and n is the number of periods.
Compound interest
With compound interest, each period's interest is added to the balance, and the next period's interest is calculated on the new balance.
A=P(1+r)n
A is the final amount. The interest earned is A−P.
Compounding periods
If interest is compounded more than once a year, divide the yearly rate and multiply the years.
Monthly: r=12annual rate, n=12×years.
Quarterly: divide by 4, multiply by 4.
8% per year compounded monthly for 5 years: r=120.08 and n=60.
Depreciation
Cars, phones and machines lose value. Declining balance depreciation takes a fixed percentage off each year:
S=V0(1−r)n
V0 is the starting value and S is the salvage value after n years.
Straight-line depreciation takes the same amount off each year, a percentage of the purchase price:
S=V0−Dn
where D is the amount lost each year. A 30 000 dollar car losing 10% of its purchase price each year loses 3000 dollars a year, so after 4 years it is worth 30000−4×3000=18000 dollars. Compare declining balance: 30000(0.9)4≈19683 dollars.
Interest
Simple
I = Prn
Linear growth
Compound
A = P(1 + r)ⁿ
Interest on interest
Exponential growth
Periods
Divide rate
Multiply time
Depreciation
S = V₀(1 - r)ⁿ
Value falls by a percent
Quick summary
Simple interest: I=Prn. Grows by the same amount each period.
Compound interest: A=P(1+r)n. Grows by the same percentage each period.
For monthly compounding, divide the yearly rate by 12 and multiply the years by 12.
Depreciation: S=V0(1−r)n.
Use logs to find how long an investment takes to reach a target.
Quiz
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Try 3 questions now
Find the simple interest on 2000 dollars at 5% per year for 4 years.
A 100 dollars
B 400 dollars
C 431 dollars
D 2400 dollars
Show answer
B: 400 dollars
2000×0.05×4=400.
3000 dollars is invested at 3% compound interest per year for 2 years. The final amount is:
A 3180.00 dollars
B 3182.70 dollars
C 3090.00 dollars
D 3300.00 dollars
Show answer
B: 3182.70 dollars
3000(1.03)2=3182.70.
Simple interest grows:
A by the same amount each year
B by the same percentage each year
C faster and faster
D slower and slower
Show answer
A: by the same amount each year
It is only paid on the principal.
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